# Power factor improve capacitors, what about resistor?

Power factor is improved by using capacitors but what about to use a resistor?

Assume an equivalent load with an impedance of 25 ohms with an angle of 25°

This yields to a power factor of the load equal to 0.9 (aprox.)

If I put a 25 ohms resistor in shunt with the previous load I get that from the source point of view the power factor now is 0.97

Why not to use resistors instead of capacitors to improve power factor?

Right answer = GE Industrial Power Systems Data Book copy.